John Murray
05/04/2023 · Primary School
Aproxime la integral definida \( \int_{1}^{5} \frac{5 x^{2}}{\sqrt{x}} d x \) mediante la suma de \( \because \quad \) Riemann por punto izquierdo, con \( n=6 \)
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Calculate the integral \( \int_{1}^{5} \frac{5 x^{2}}{\sqrt{x}} dx \).
Evaluate the integral by following steps:
- step0: Evaluate using formulas and rules:
\(\int_{1}^{5} \frac{5x^{2}}{\sqrt{x}} dx\)
- step1: Evaluate the power:
\(\int_{1}^{5} \frac{5x^{2}}{x^{\frac{1}{2}}} dx\)
- step2: Simplify the expression:
\(\int_{1}^{5} 5x^{\frac{3}{2}} dx\)
- step3: Evaluate the integral:
\(\int 5x^{\frac{3}{2}} dx\)
- step4: Use properties of integrals:
\(5\times \int x^{\frac{3}{2}} dx\)
- step5: Evaluate the integral:
\(5\times \frac{2}{5}x^{\frac{5}{2}}\)
- step6: Calculate:
\(2x^{\frac{5}{2}}\)
- step7: Return the limits:
\(\left(2x^{\frac{5}{2}}\right)\bigg |_{1}^{5}\)
- step8: Calculate the value:
\(2\times 5^{\frac{5}{2}}-2\)
- step9: Transform the expression:
\(2\times 25\sqrt{5}-2\)
- step10: Simplify:
\(50\sqrt{5}-2\)
La integral definida \( \int_{1}^{5} \frac{5 x^{2}}{\sqrt{x}} dx \) es igual a \( 50\sqrt{5}-2 \).
Ahora, vamos a aproximar esta integral mediante la suma de Riemann por punto izquierdo con \( n=6 \). Para hacer esto, primero necesitamos encontrar el ancho de cada subintervalo, que se calcula como \( \Delta x = \frac{b-a}{n} \), donde \( a=1 \), \( b=5 \) y \( n=6 \).
Calculamos el ancho de cada subintervalo:
\[ \Delta x = \frac{5-1}{6} = \frac{4}{6} = \frac{2}{3} \]
Ahora, calculamos la suma de Riemann por punto izquierdo con \( n=6 \):
\[ \sum_{i=1}^{6} f(x_i) \Delta x \]
Donde \( x_i = a + (i-1) \Delta x \) y \( f(x) = \frac{5 x^{2}}{\sqrt{x}} \).
Calculamos los valores de \( x_i \) y \( f(x_i) \) para cada \( i \) y luego multiplicamos por \( \Delta x \) para obtener la suma de Riemann por punto izquierdo.
Quick Answer
Para aproximar la integral \( \int_{1}^{5} \frac{5 x^{2}}{\sqrt{x}} dx \) con la suma de Riemann por punto izquierdo y \( n=6 \), primero calcula el ancho de cada subintervalo, \( \Delta x = \frac{2}{3} \). Luego, calcula \( f(x_i) \) para cada \( x_i = a + (i-1) \Delta x \) y sumarlos multiplicados por \( \Delta x \).
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