Reese Romero
12/31/2023 · Elementary School
9. Resolver la ecuación matricial \[ X A^{T}+X B=C \] siendo \[ A=\left(\begin{array}{ccc}0 & -1 & 5 \\ 3 & 0 & 3 \\ -4 & -1 & 1\end{array}\right) \quad B=\left(\begin{array}{ccc}1 & -3 & 5 \\ 4 & 3 & 5 \\ -3 & -1 & 2\end{array}\right) \quad \text { y } \quad C=\left(\begin{array}{ccc}1 & 0 & 2 \\ 0 & -1 & 0\end{array}\right) \]
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Para resolver la ecuación matricial \( X A^{T}+X B=C \), se multiplica \( A \) por su transpuesta \( A^{T} \), luego se multiplica \( X \) por \( A^{T} \) y \( B \) por \( A^{T} \). Se obtiene un sistema de ecuaciones lineales que se debe resolver para encontrar los valores de \( X \).
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