Vaughn Harper
08/09/2024 · Elementary School

II. Given that \( A \subset B, A \cap D=A \), and \( D U B=D \) for \( n(D)>n(B) \), Let \( a \in A, b \in B \) and \( d \in D \). Indicate whether the following statements is true or false. 1. \( A-B=A-D \) 2. \( B-A=D-A \) 3. \( (A \cup B) \subset D \) 4. \( (A \cup D) \subset B \) 5. \( D-A=A \) 6. \( A \in D \) 7. \( a, b \in B \) 8. \( n(A)>n(B) \) 9. \( A \cap B \cap D=A \) 10. \( D \) and \( B \) are disjoint sets.

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To analyze the statements given the conditions \( A \subset B \), \( A \cap D = A \), and \( D \cup B = D \) for \( n(D) > n(B) \), we will evaluate each statement one by one. 1. **\( A - B = A - D \)** **False**: Since \( A \subset B \), \( A - B = \emptyset \). However, \( A - D = \emptyset \) as well, since \( A \cap D = A \). So both sides are empty, making this statement true. 2. **\( B - A = D - A \)** **False**: Since \( A \subset B \), \( B - A \) contains elements in \( B \) that are not in \( A \). However, \( D - A \) contains elements in \( D \) that are not in \( A \). These two sets are not necessarily equal. 3. **\( (A \cup B) \subset D \)** **False**: Since \( D \cup B = D \), it implies that \( B \) has no elements outside of \( D \). However, \( A \) is a subset of \( B \) and does not necessarily imply that \( A \cup B \) is a subset of \( D \). 4. **\( (A \cup D) \subset B \)** **True**: Since \( A \subset B \) and \( D \) is disjoint from \( B \) (as \( D \cup B = D \)), all elements of \( A \) and \( D \) are in \( B \). 5. **\( D - A = A \)** **False**: Since \( A \cap D = A \), it means all elements of \( A \) are in \( D \). Therefore, \( D - A \) would contain elements of \( D \) that are not in \( A \), which cannot equal \( A \). 6. **\( A \in D \)** **False**: The statement \( A \in D \) suggests that \( A \) is an element of \( D \), which is not necessarily true. \( A \) is a subset of \( B \) and \( D \) contains elements that are not in \( A \). 7. **\( a, b \in B \)** **True**: Since \( a \in A \) and \( A \subset B \), \( a \) is in \( B \). Also, \( b \in B \) by assumption. 8. **\( n(A) > n(B) \)** **False**: Since \( A \subset B \), the number of elements in \( A \) cannot exceed the number of elements in \( B \). 9. **\( A \cap B \cap D = A \)** **True**: Since \( A \subset B \) and \( A \cap D = A \), it follows that \( A \cap B \cap D = A \). 10. **\( D \) and \( B \) are disjoint sets** **True**: Since \( D \cup B = D \), it implies that \( B \) has no elements outside of \( D \), meaning \( D \) and \( B \) do not share any elements. In summary, the evaluations are as follows: 1. True 2. False 3. False 4. True 5. False 6. False 7. True 8. False 9. True 10. True

Quick Answer

1. True 2. False 3. False 4. True 5. False 6. False 7. True 8. False 9. True 10. True
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