The numbers on two consecutively numbered gym lockers have a sum of 121 . What are the locker numbers?

Let the two consecutively numbered gym lockers be represented as \( x \) and \( x + 1 \). According to the problem, the sum of these two locker numbers is 121. We can set up the equation: \[ x + (x + 1) = 121 \] Simplifying this equation: \[ 2x + 1 = 121 \] Subtracting 1 from both sides: \[ 2x = 120 \] Dividing both sides by 2: \[ x = 60 \] Thus, the first locker number is \( 60 \) and the second locker number is: \[ x + 1 = 60 + 1 = 61 \] Therefore, the locker numbers are **60 and 61**.