phove that $$ \sqrt{2} $$ \iebetween 14 aed

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$$ \sqrt{2} $$ is between 1 and 2. To prove that $$ \sqrt{2} $$ is between 1 and 2, we can show that $$ 1^2 < 2 < 2^2 $$. 1. First, we calculate $$ 1^2 $$: $$ 1^2 = 1 $$ 2. Next, we check if $$ 1^2 < 2 $$: $$ 1 < 2 \quad \text{(True)} $$ 3. Now, we calculate $$ 2^2 $$: $$ 2^2 = 4 $$ 4. Finally, we check if $$ 2 < 2^2 $$: $$ 2 < 4 \quad \text{(True)} $$ Since both inequalities $$ 1 < \sqrt{2} < 2 $$ hold true, we conclude that: $$ 1 < \sqrt{2} < 2 $$ Thus, we have proven that $$ \sqrt{2} $$ is between 1 and 2.

phove that \( \sqrt{2} \) \iebetween 14 aed

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phove that \( \sqrt{2} \) \iebetween 14 aed

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