Owen Chadwick
06/30/2023 · Senior High School

1. Evaluate the following: Hint: Inverse trigonometry (a) (2 points) \[ \int \frac{1}{x \sqrt{4 x^{2}-2}} d x \]

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Calculate the integral \( \int \frac{1}{x \sqrt{4 x^{2}-2}} dx \). Evaluate the integral by following steps: - step0: Evaluate using formulas and rules: \(\int \frac{1}{x\sqrt{4x^{2}-2}} dx\) - step1: Evaluate the power: \(\int \frac{1}{x\left(4x^{2}-2\right)^{\frac{1}{2}}} dx\) - step2: Rewrite the expression: \(\int \frac{1}{x\times 4^{\frac{1}{2}}\left(x^{2}-\frac{1}{2}\right)^{\frac{1}{2}}} dx\) - step3: Rewrite the expression: \(\int \frac{1}{2}\times \frac{1}{x\left(x^{2}-\frac{1}{2}\right)^{\frac{1}{2}}\left(x^{2}-\frac{1}{2}\right)^{\frac{1}{2}}} dx\) - step4: Evaluate the integral: \(\frac{1}{2}\times \int \frac{1}{x\left(x^{2}-\frac{1}{2}\right)^{\frac{1}{2}}\left(x^{2}-\frac{1}{2}\right)^{\frac{1}{2}}} dx\) - step5: Evaluate the integral: \(\frac{1}{2}\times \frac{2}{\sqrt{2}}\times \operatorname{arcsec}\left(\sqrt{2}\times \left|x\right|\right)\) - step6: Calculate: \(\frac{1}{\sqrt{2}}\times \operatorname{arcsec}\left(\sqrt{2}\times \left|x\right|\right)\) - step7: Rewrite the expression: \(\frac{\operatorname{arcsec}\left(\sqrt{2}\times \left|x\right|\right)}{\sqrt{2}}\) - step8: Add the constant of integral C: \(\frac{\operatorname{arcsec}\left(\sqrt{2}\times \left|x\right|\right)}{\sqrt{2}} + C, C \in \mathbb{R}\) The result of the integral \(\int \frac{1}{x \sqrt{4 x^{2}-2}} dx\) is \(\frac{\operatorname{arcsec}(\sqrt{2}\times |x|)}{\sqrt{2}} + C\), where \(C\) is an arbitrary constant.

Quick Answer

The integral \(\int \frac{1}{x \sqrt{4 x^{2}-2}} dx\) evaluates to \(\frac{\operatorname{arcsec}(\sqrt{2}\times |x|)}{\sqrt{2}} + C\).
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