Patel Spencer
08/07/2024 · High School
(bx) \( \sqrt{6}-\sqrt{3} \cdot \sqrt{2}= \)
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
To simplify the expression \( \sqrt{6} - \sqrt{3} \cdot \sqrt{2} \), we first simplify the term \( \sqrt{3} \cdot \sqrt{2} \).
Using the property of square roots that states \( \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} \), we have:
\[
\sqrt{3} \cdot \sqrt{2} = \sqrt{3 \cdot 2} = \sqrt{6}
\]
Now we can substitute this back into the original expression:
\[
\sqrt{6} - \sqrt{3} \cdot \sqrt{2} = \sqrt{6} - \sqrt{6}
\]
This simplifies to:
\[
0
\]
Thus, the final answer is:
\[
\boxed{0}
\]
Quick Answer
The expression simplifies to 0.
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