\( 1 \leftarrow \) The sign outside a company's headquarters has a width of 87 feet and an area of 10,527 square feet. Find the height (or length) of the sign. Determine the appropriate formula that is needed to solve this problem. Choose the correct answer below. A. area \( = \) length + width B. width \( = \) length \( \cdot \) area C. length \( = \) width + area Let \( x= \) the \( = \) length \( ~ \cdot \) width

Si se sabe que \( \beta \in\left\langle 135^{\circ} ; 210^{\circ}\right\rceil \), indica la variacion \( E=\sqrt{2} \cos \beta+1 \)

Q2- A- Find an integrating factor for the following equation: B- solve the equation and find the general answer: C- find the privet answer if \( y\left(\frac{\pi}{4}\right)=\pi \) \( 2+\left(\frac{x}{y}-\frac{\sin y}{\sqrt{y}}\right) y^{\prime}=0 \)

10. Rewrite the equation of the circle \( x^{2}+(y-4)^{2}=6 \) in general form.

If \( M(3,6), N(-2,-2) \), and \( O(5,3) \) are the vertices of \( \triangle M N O \), the slope of the altitude from \( M \) to \( \overline{N O} \) is and the slope of the altitude from \( N \) to \( \overline{M O} \) is

1. \( a^{2}+a \)