36.7 ta nonni 8 odamga teng bo'lib bering. Juda oson masal ekan ku, deyishingiz mumkin. Haqiqatdan ham, har bir nonr 8 bo'lakka bo'lib, har bir odamga 7 bo'lakdan bo'lib beri? masalani yechish mumkin. Biroq, hamma gap shund qadimgi Misrliklar nonni imkoni boricha kam bo'laklark bolib, bu masalani yechishgan. Siz ham bu yechimni topish urinib ko'ring!

solve each of the following equation:- \( \left(\frac{1}{7}\right)^{x}=49 \)

\( \left. \begin{array} { l } { y = x ^ { 3 } ( 7 - x | } \\ { f ( x ) > 0 \quad \rightarrow x ^ { 3 } + 7 + x > 0 } \end{array} \right. \)

\( f(x)=-\frac{3}{2} x^{3}+\frac{2}{5} x^{2}-4 \) a. \( f^{\prime}(x)=-\frac{5}{x^{2}}+\frac{6}{x^{3}} \) b. \( f^{\prime}(x)=\frac{3}{2} \cdot \sqrt{x}-\frac{5}{3} \sqrt[3]{x^{2}} \) c. \( f^{\prime}(x)=\frac{6}{x^{4}}-\frac{6}{x^{3}}-4 \) d. \( f^{\prime}(x)=-\frac{4}{2} x^{2}+\frac{4}{5} x \)

\( \lim _{x \rightarrow 3} \frac{\sqrt{x+1}-2}{x-3} \) a. \( 12,2 / 8 \) b. \( 3,2 / 3 \) c. 0,0 d. 0,0

Calculez en détaillant les étapes: \[ 1 . \frac{-3}{8}-\left(\frac{12}{2^{3}}-2^{-1}\right)^{3} \]