Munoz Stanley
01/30/2024 · Primary School
a. \( { }^{2} \log 6+{ }^{2} \log 4-{ }^{2} \log 3 \) b. \( { }^{3} \log 3 \sqrt{3}-{ }^{3} \log 2 \sqrt{3}+{ }^{3} \log 54 \)
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
To simplify the logarithmic expressions, we will use the properties of logarithms, including the change of base formula and the properties of logarithms such as \( \log a + \log b = \log(ab) \) and \( \log a - \log b = \log\left(\frac{a}{b}\right) \).
### Part a: \( { }^{2} \log 6 + { }^{2} \log 4 - { }^{2} \log 3 \)
Using the property of logarithms:
\[
{ }^{2} \log 6 + { }^{2} \log 4 = { }^{2} \log (6 \cdot 4) = { }^{2} \log 24
\]
Now, we can combine this with the subtraction:
\[
{ }^{2} \log 24 - { }^{2} \log 3 = { }^{2} \log \left(\frac{24}{3}\right) = { }^{2} \log 8
\]
Since \( 8 = 2^3 \), we can express this as:
\[
{ }^{2} \log 8 = { }^{2} \log (2^3) = 3 \cdot { }^{2} \log 2
\]
Thus, the simplified expression for part a is:
\[
3 \cdot { }^{2} \log 2
\]
### Part b: \( { }^{3} \log 3 \sqrt{3} - { }^{3} \log 2 \sqrt{3} + { }^{3} \log 54 \)
First, we simplify \( { }^{3} \log 3 \sqrt{3} \) and \( { }^{3} \log 2 \sqrt{3} \):
\[
{ }^{3} \log 3 \sqrt{3} = { }^{3} \log (3^{1} \cdot 3^{1/2}) = { }^{3} \log (3^{3/2}) = \frac{3}{2} \cdot { }^{3} \log 3
\]
\[
{ }^{3} \log 2 \sqrt{3} = { }^{3} \log (2 \cdot 3^{1/2}) = { }^{3} \log 2 + { }^{3} \log 3^{1/2} = { }^{3} \log 2 + \frac{1}{2} { }^{3} \log 3
\]
Now substituting these into the original expression:
\[
\frac{3}{2} { }^{3} \log 3 - \left( { }^{3} \log 2 + \frac{1}{2} { }^{3} \log 3 \right) + { }^{3} \log 54
\]
Combining the terms:
\[
\left( \frac{3}{2} { }^{3} \log 3 - \frac{1}{2} { }^{3} \log 3 \right) - { }^{3} \log 2 + { }^{3} \log 54
\]
This simplifies to:
\[
{ }^{3} \log 3 - { }^{3} \log 2 + { }^{3} \log 54
\]
Now, we can combine the logarithms:
\[
{ }^{3} \log \left( \frac{3 \cdot 54}{2} \right)
\]
Calculating \( \frac{3 \cdot 54}{2} \):
\[
3 \cdot 54 = 162 \quad \text{and} \quad \frac{162}{2} = 81
\]
Thus, we have:
\[
{ }^{3} \log 81
\]
Since \( 81 = 3^4 \), we can express this as:
\[
{ }^{3} \log (3^4) = 4 \cdot { }^{3} \log 3
\]
So the simplified expression for part b is:
\[
4 \cdot { }^{3} \log 3
\]
### Final Answers:
a. \( 3 \cdot { }^{2} \log 2 \)
b. \( 4 \cdot { }^{3} \log 3 \)
Quick Answer
a. \( 3 \cdot { }^{2} \log 2 \)
b. \( 4 \cdot { }^{3} \log 3 \)
Answered by UpStudy AI and reviewed by a Professional Tutor
UpStudy ThothAI
Self-Developed and Ever-Improving
Thoth AI product is constantly being upgraded and optimized.
Covers All Major Subjects
Capable of handling homework in math, chemistry, biology, physics, and more.
Instant and Accurate
Provides immediate and precise solutions and guidance.
Try Now
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text
Enter your question here…
By image
Re-Upload
Submit