Bowers Jimenez
09/13/2023 · Junior High School

Draw a diagram for the following situations. Calculate the distance and displacement in each of the following situations. Include a direction (example: north or northwest) with your answer. 1. Amy runs 2 miles south, then turns around and runs 3 miles north 2. Jermaine runs exactly 2 laps around a 400 meter track 3. Derrick crawls 4 feet south, and then turns east and crawls 6 feet.

UpStudy ThothAI Solution

Tutor-Verified Answer

Step-by-step Solution

Let's analyze each situation step by step, calculate the distance and displacement, and include directions. ### 1. Amy's Run - **Path**: Amy runs 2 miles south, then turns around and runs 3 miles north. - **Distance**: - 2 miles (south) + 3 miles (north) = 5 miles - **Displacement**: - She ends up 1 mile north of her starting point (3 miles north - 2 miles south). - **Displacement**: 1 mile north ### Diagram for Amy: ``` Starting Point | | (2 miles south) | v (A) --------------------> (B) | (3 miles north) | ^ ``` - **Distance**: 5 miles - **Displacement**: 1 mile north --- ### 2. Jermaine's Run - **Path**: Jermaine runs exactly 2 laps around a 400-meter track. - **Distance**: - 2 laps × 400 meters/lap = 800 meters - **Displacement**: - Since he returns to the starting point after 2 laps, the displacement is 0 meters. ### Diagram for Jermaine: ``` (A)--------------------(B) | | | | | | | | (D)--------------------(C) ``` - **Distance**: 800 meters - **Displacement**: 0 meters --- ### 3. Derrick's Crawl - **Path**: Derrick crawls 4 feet south, then turns east and crawls 6 feet. - **Distance**: - 4 feet (south) + 6 feet (east) = 10 feet - **Displacement**: - To find the displacement, we can use the Pythagorean theorem: - \( d = \sqrt{(4^2 + 6^2)} = \sqrt{16 + 36} = \sqrt{52} \approx 7.21 \) feet - The direction can be found using the tangent function: - \( \tan(\theta) = \frac{opposite}{adjacent} = \frac{4}{6} \) - \( \theta = \tan^{-1}(\frac{4}{6}) \approx 33.69^\circ \) south of east. ### Diagram for Derrick: ``` Starting Point | | (4 feet south) | v (A) | | (6 feet east) --------------------> (B) ``` - **Distance**: 10 feet - **Displacement**: Approximately 7.21 feet at an angle of 33.69° south of east. --- ### Summary of Results: 1. **Amy**: Distance = 5 miles, Displacement = 1 mile north 2. **Jermaine**: Distance = 800 meters, Displacement = 0 meters 3. **Derrick**: Distance = 10 feet, Displacement = approximately 7.21 feet at 33.69° south of east.

Quick Answer

1. Amy: Distance = 5 miles, Displacement = 1 mile north 2. Jermaine: Distance = 800 meters, Displacement = 0 meters 3. Derrick: Distance = 10 feet, Displacement = approximately 7.21 feet at 33.69° south of east.
Answered by UpStudy AI and reviewed by a Professional Tutor
UpStudy ThothAI
Self-Developed and Ever-Improving
Thoth AI product is constantly being upgraded and optimized.
Covers All Major Subjects
Capable of handling homework in math, chemistry, biology, physics, and more.
Instant and Accurate
Provides immediate and precise solutions and guidance.
Try Now
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text

Enter your question here…

By image
Re-Upload
Uploaded Files
xxxx.png0%
Submit
📸 STUDY CAN BE A REAL STRUGGLE
Why Not UpStudy It?
Select your plan below
Premium

You can enjoy

  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to answer and
    solution
Basic
  • Limited Solutions