If \( \frac{7}{8} \) is multiplied by \( \frac{4}{7} \), will the product be greater than either of the 2 factors? Explain. The product will be \( \square \) of the 2 factors. When multiplying 2 fractions \( \square \), the product is alway \( \square \) the \( \square \) being multiplied.

To determine whether the product of \( \frac{7}{8} \) and \( \frac{4}{7} \) is greater than either of the two factors, we first calculate the product: \[ \frac{7}{8} \times \frac{4}{7} = \frac{7 \times 4}{8 \times 7} = \frac{28}{56} = \frac{1}{2} \] Now, we compare the product \( \frac{1}{2} \) with the two factors \( \frac{7}{8} \) and \( \frac{4}{7} \). 1. Comparing \( \frac{1}{2} \) with \( \frac{7}{8} \): - Since \( \frac{7}{8} = 0.875 \) and \( \frac{1}{2} = 0.5 \), we see that \( \frac{1}{2} < \frac{7}{8} \). 2. Comparing \( \frac{1}{2} \) with \( \frac{4}{7} \): - Since \( \frac{4}{7} \approx 0.571 \), we see that \( \frac{1}{2} < \frac{4}{7} \). Thus, the product \( \frac{1}{2} \) is less than both \( \frac{7}{8} \) and \( \frac{4}{7} \). Now, we can fill in the blanks in your statement: The product will be **less than** the 2 factors. When multiplying 2 fractions **less than 1**, the product is always **less than** the **factors** being multiplied.