Fitzgerald Mathis
02/14/2023 · Primary School
\( \frac { ( \frac { 105 } { 99 } + \frac { 2 } { 3 } + 1 , \sqrt { 27 } ) ^ { - 2 } } { \sqrt[ 3 ] { 2 - \frac { 55 } { 27 } } } = \)
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Step-by-step Solution
To solve the expression
\[
\frac { ( \frac { 105 } { 99 } + \frac { 2 } { 3 } + 1 , \sqrt { 27 } ) ^ { - 2 } } { \sqrt[ 3 ] { 2 - \frac { 55 } { 27 } } },
\]
we will break it down step by step.
### Step 1: Simplify \( \frac{105}{99} \)
First, we simplify \( \frac{105}{99} \):
\[
\frac{105}{99} = \frac{105 \div 3}{99 \div 3} = \frac{35}{33}.
\]
### Step 2: Simplify \( \frac{2}{3} + 1 \)
Next, we simplify \( \frac{2}{3} + 1 \):
\[
1 = \frac{3}{3} \quad \Rightarrow \quad \frac{2}{3} + 1 = \frac{2}{3} + \frac{3}{3} = \frac{5}{3}.
\]
### Step 3: Combine the fractions
Now we combine \( \frac{35}{33} + \frac{5}{3} \):
To add these fractions, we need a common denominator. The least common multiple of 33 and 3 is 33.
\[
\frac{5}{3} = \frac{5 \times 11}{3 \times 11} = \frac{55}{33}.
\]
Now we can add:
\[
\frac{35}{33} + \frac{55}{33} = \frac{35 + 55}{33} = \frac{90}{33}.
\]
We can simplify \( \frac{90}{33} \):
\[
\frac{90 \div 3}{33 \div 3} = \frac{30}{11}.
\]
### Step 4: Calculate \( \sqrt{27} \)
Next, we calculate \( \sqrt{27} \):
\[
\sqrt{27} = \sqrt{9 \times 3} = \sqrt{9} \cdot \sqrt{3} = 3\sqrt{3}.
\]
### Step 5: Form the tuple and raise to the power of -2
Now we have:
\[
\left( \frac{30}{11}, 3\sqrt{3} \right).
\]
We need to find the magnitude of this tuple:
\[
\sqrt{\left( \frac{30}{11} \right)^2 + (3\sqrt{3})^2}.
\]
Calculating each part:
\[
\left( \frac{30}{11} \right)^2 = \frac{900}{121},
\]
\[
(3\sqrt{3})^2 = 9 \cdot 3 = 27.
\]
Now we convert 27 to a fraction with a denominator of 121:
\[
27 = \frac{27 \cdot 121}{121} = \frac{3267}{121}.
\]
Now we can add:
\[
\sqrt{\frac{900}{121} + \frac{3267}{121}} = \sqrt{\frac{900 + 3267}{121}} = \sqrt{\frac{4167}{121}} = \frac{\sqrt{4167}}{11}.
\]
### Step 6: Raise to the power of -2
Now we raise this to the power of -2:
\[
\left( \frac{\sqrt{4167}}{11} \right)^{-2} = \frac{11^2}{4167} = \frac{121}{4167}.
\]
### Step 7: Simplify the denominator \( \sqrt[3]{2 - \frac{55}{27}} \)
Now we simplify the denominator:
\[
2 - \frac{55}{27} = \frac{2 \cdot 27}{27} - \frac{55}{27} = \frac{54 - 55}{27} = \frac{-1}{27}.
\]
Now we find the cube root:
\[
\sqrt[3]{\frac{-1}{27}} = \frac{\sqrt[3]{-1}}{\sqrt[3]{27}} = \frac{-1}{3}.
\]
### Step 8: Final calculation
Now we can substitute back into the expression:
\[
\frac{\frac{121}{4167}}{\frac{-1}{3}} = \frac{121}{4167} \cdot \left(-3\right) = \frac{-363}{4167}.
\]
Thus, the
Quick Answer
\(\frac{-363}{4167}\)
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