Hardy Wright
08/24/2024 · Elementary School
Question 8 (Mandatory) (1 point) If Tina starts out at \( 10 \mathrm{~m} / \mathrm{s} \), and in 10 s speeds up to \( 20 \mathrm{~m} / \mathrm{s} \), what is her acceleration? \( 100 \mathrm{~m} / \mathrm{s} / \mathrm{s} \) \( 2 \mathrm{~m} / \mathrm{s} / \mathrm{s} \) \( 1 \mathrm{~m} / \mathrm{s} / \mathrm{s} \) \( 3 \mathrm{~m} / \mathrm{s} / \mathrm{s} \)
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Tutor-Verified Answer
Step-by-step Solution
To calculate Tina's acceleration, we can use the formula for acceleration:
\[
a = \frac{\Delta v}{\Delta t}
\]
where:
- \( \Delta v \) is the change in velocity,
- \( \Delta t \) is the change in time.
In this case:
- Initial velocity (\( v_i \)) = \( 10 \, \text{m/s} \)
- Final velocity (\( v_f \)) = \( 20 \, \text{m/s} \)
- Time interval (\( \Delta t \)) = \( 10 \, \text{s} \)
First, we calculate the change in velocity (\( \Delta v \)):
\[
\Delta v = v_f - v_i = 20 \, \text{m/s} - 10 \, \text{m/s} = 10 \, \text{m/s}
\]
Now, we can calculate the acceleration:
\[
a = \frac{\Delta v}{\Delta t} = \frac{10 \, \text{m/s}}{10 \, \text{s}} = 1 \, \text{m/s}^2
\]
Therefore, Tina's acceleration is \( 1 \, \text{m/s}^2 \).
The correct answer is:
\( 1 \, \text{m/s} / \text{s} \)
Quick Answer
\( 1 \, \text{m/s}^2 \)
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