Hardy Wright
08/24/2024 · Elementary School

Question 8 (Mandatory) (1 point) If Tina starts out at \( 10 \mathrm{~m} / \mathrm{s} \), and in 10 s speeds up to \( 20 \mathrm{~m} / \mathrm{s} \), what is her acceleration? \( 100 \mathrm{~m} / \mathrm{s} / \mathrm{s} \) \( 2 \mathrm{~m} / \mathrm{s} / \mathrm{s} \) \( 1 \mathrm{~m} / \mathrm{s} / \mathrm{s} \) \( 3 \mathrm{~m} / \mathrm{s} / \mathrm{s} \)

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To calculate Tina's acceleration, we can use the formula for acceleration: \[ a = \frac{\Delta v}{\Delta t} \] where: - \( \Delta v \) is the change in velocity, - \( \Delta t \) is the change in time. In this case: - Initial velocity (\( v_i \)) = \( 10 \, \text{m/s} \) - Final velocity (\( v_f \)) = \( 20 \, \text{m/s} \) - Time interval (\( \Delta t \)) = \( 10 \, \text{s} \) First, we calculate the change in velocity (\( \Delta v \)): \[ \Delta v = v_f - v_i = 20 \, \text{m/s} - 10 \, \text{m/s} = 10 \, \text{m/s} \] Now, we can calculate the acceleration: \[ a = \frac{\Delta v}{\Delta t} = \frac{10 \, \text{m/s}}{10 \, \text{s}} = 1 \, \text{m/s}^2 \] Therefore, Tina's acceleration is \( 1 \, \text{m/s}^2 \). The correct answer is: \( 1 \, \text{m/s} / \text{s} \)

Quick Answer

\( 1 \, \text{m/s}^2 \)
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