8. Use a pronoun for the words in brackets a) Junald is good at designing. The costumes are (Junald's) responsibility, b) Noxolo asked Carla to help (Noxolo), c) The play will be great. (The play's) auditions are next week, Complete the paragraph using the following words mlintes, nsenifa, notes. First, Carla took \( \longrightarrow \) then she wrote the out in full. The meeting followed the topics listed in the

Car repairs: Let \( E \) be the event that a new car requires engine work under warranty and let \( T \) be the event that the car requires transmission work under warranty. Suppose that \( P(E)=0.07, P(T)=0.08, P(E \) and \( T)=0.05 \). (a) Find the probability that the car needs work on either the engine, the transmission, or both. (b) Find the probability that the car needs no work on the transmission. Part 1 of 2 (a) Find the probability that the car needs work on either the engine, the transmission, or both. Tart 2 of 2 Tb) Find the probability that the car needs work on either the engine, the transmission, or both is the car needs no work on the transmission. The probability that the car needs no work on the transmission is (b).

What is the product of \(4\) and the absolute value of \(-8\)?

Simplify the following to a single trigonometric function, without the use of a calculator. \( \frac{\cos \left(90^{\circ}-\alpha\right) \sin \left(-\alpha-540^{\circ}\right)}{\tan 225^{\circ}+\sin \alpha \cdot \sin \left(180^{\circ}+\alpha\right)} \) Siven: \( 1-\cos \theta=2 \sin ^{2} \theta \) 5.4.1 Show that the equation can be written as: \( (2 \cos \theta+1)(\cos \theta-1)=0 \).

A metallurgist has one alloy containing \( 23 \% \) aluminum and another containing \( 54 \% \) aluminum. How many pounds of each alloy must he use to make 50 pounds of a third alloy containing \( 53 \% \) aluminum? (Round to two decimal places if necessary.) Answer How to enter your answer (opens in new window) pounds of the alloy containing \( 23 \% \) aluminum keyboard Shortcuts

Give an exact answer. \[ \begin{array}{l}10(0.4+0.5 g)=4 g \\ g=\end{array} \]