Owen Mcfarlane
07/06/2024 · Elementary School

\( \frac{1-1}{\text { 1.) } 3 c+12} \square \)

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Step-by-step Solution

The expression you provided is \( \frac{1-1}{3c+12} \square \). First, let's simplify the expression in the numerator: \[ 1 - 1 = 0 \] So, the expression simplifies to: \[ \frac{0}{3c + 12} \] Since the numerator is 0, the entire fraction evaluates to 0, regardless of the value of the denominator (as long as the denominator is not zero). Thus, the simplified expression is: \[ 0 \square \] If you meant to ask for a specific operation or value to replace the square ( \(\square\) ), please clarify!

Quick Answer

The expression simplifies to 0.
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