Klein Lee
11/12/2023 · Junior High School

he length (in pages) of math research projects is giver elow. Using this information, calculate the range, ariance, and standard deviation. \[ 19,16,34,11,29,24,16,299,21 \] ange \( = \) ariance \( = \) tandard deviation \( = \)

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To calculate the range, variance, and standard deviation of the given data set, we will follow these steps: 1. **Calculate the Range**: The range is the difference between the maximum and minimum values in the data set. Given data: \( 19, 16, 34, 11, 29, 24, 16, 299, 21 \) - Maximum value = 299 - Minimum value = 11 \[ \text{Range} = \text{Maximum} - \text{Minimum} = 299 - 11 = 288 \] 2. **Calculate the Variance**: Variance is calculated using the formula: \[ \text{Variance} = \frac{\sum (x_i - \mu)^2}{N} \] where \( \mu \) is the mean of the data set, \( x_i \) are the individual data points, and \( N \) is the number of data points. - First, calculate the mean (\( \mu \)): \[ \mu = \frac{\sum x_i}{N} = \frac{19 + 16 + 34 + 11 + 29 + 24 + 16 + 299 + 21}{9} = \frac{ 19 + 16 + 34 + 11 + 29 + 24 + 16 + 299 + 21 }{9} = \frac{ 449 }{9} \approx 49.89 \] - Next, calculate the squared differences from the mean: \[ \begin{align*} (19 - 49.89)^2 & \approx 935.61 \\ (16 - 49.89)^2 & \approx 1135.61 \\ (34 - 49.89)^2 & \approx 252.01 \\ (11 - 49.89)^2 & \approx 1495.61 \\ (29 - 49.89)^2 & \approx 436.01 \\ (24 - 49.89)^2 & \approx 653.61 \\ (16 - 49.89)^2 & \approx 1135.61 \\ (299 - 49.89)^2 & \approx 61761.61 \\ (21 - 49.89)^2 & \approx 835.61 \\ \end{align*} \] - Now sum these squared differences: \[ \sum (x_i - \mu)^2 \approx 935.61 + 1135.61 + 252.01 + 1495.61 + 436.01 + 653.61 + 1135.61 + 61761.61 + 835.61 \approx 67066.5 \] - Finally, calculate the variance: \[ \text{Variance} = \frac{67066.5}{9} \approx 7440.72 \] 3. **Calculate the Standard Deviation**: The standard deviation is the square root of the variance. \[ \text{Standard Deviation} = \sqrt{\text{Variance}} \approx \sqrt{7440.72} \approx 86.3 \] ### Summary of Results: - Range: \( 288 \) - Variance: \( 7440.72 \) - Standard Deviation: \( 86.3 \) Thus, the final answers are: - Range \( = 288 \) - Variance \( \approx 7440.72 \) - Standard Deviation \( \approx 86.3 \)

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Range \( = 288 \) Variance \( \approx 7440.72 \) Standard Deviation \( \approx 86.3 \)
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