Addition Problem: \( 0^{\prime}-73 / 16^{\prime \prime}+9^{\prime}-0 \) 1/2" \( +27^{\prime}-41 / 4 " \) " \( = \) \( 36^{\prime}-115 / 8^{\prime \prime} \) \( 36^{\prime}-111 / 4^{\prime \prime} \) \( 36^{\prime}-1115 / 16^{\prime \prime} \)

To solve the addition problem, we need to convert all measurements to a common unit, typically inches, and then perform the arithmetic. 1. **Convert all measurements to inches:** - \( 0^{\prime} - 73 / 16^{\prime \prime} + 9^{\prime} - 0 \frac{1}{2}'' + 27^{\prime} - 41 / 4'' \) - Convert feet to inches: - \( 0^{\prime} = 0 \) inches - \( 9^{\prime} = 9 \times 12 = 108 \) inches - \( 27^{\prime} = 27 \times 12 = 324 \) inches - Convert the fractions: - \( -73 / 16^{\prime \prime} = -\frac{73}{16} \) inches - \( -0 \frac{1}{2}'' = -\frac{1}{2} = -\frac{1}{2} \) inches - \( -41 / 4'' = -\frac{41}{4} \) inches 2. **Combine all the terms:** - Total inches = \( 0 - \frac{73}{16} + 108 - \frac{1}{2} + 324 - \frac{41}{4} \) 3. **Convert all fractions to a common denominator:** - The least common multiple of 16, 2, and 4 is 16. - Convert each term: - \( -\frac{73}{16} \) stays the same. - \( -\frac{1}{2} = -\frac{8}{16} \) - \( -\frac{41}{4} = -\frac{164}{16} \) 4. **Combine the fractions:** - Total inches = \( 0 + 108 + 324 - \frac{73}{16} - \frac{8}{16} - \frac{164}{16} \) - Combine the whole numbers: \( 108 + 324 = 432 \) inches - Combine the fractions: \( -\frac{73 + 8 + 164}{16} = -\frac{245}{16} \) 5. **Final calculation:** - Total = \( 432 - \frac{245}{16} \) - Convert 432 to sixteenths: \( 432 = \frac{432 \times 16}{16} = \frac{6912}{16} \) - Combine: \( \frac{6912 - 245}{16} = \frac{6667}{16} \) 6. **Convert back to feet and inches:** - Divide \( 6667 \) by \( 16 \): - \( 6667 \div 16 = 416 \) remainder \( 3 \) - This means \( 416 \) inches and \( 3 \) sixteenths of an inch. - Convert \( 416 \) inches to feet: \( 416 \div 12 = 34 \) feet with a remainder of \( 8 \) inches. 7. **Final result:** - The final answer is \( 34^{\prime} - 3 / 16^{\prime \prime} \). Thus, the answer is: \[ \boxed{34^{\prime} - 3 / 16^{\prime \prime}} \]