Fuentes Flynn
09/01/2023 · Primary School
\( 1-(y-8), 2=6 \) \( 2 \cdot 3 \cdot x-5+1: 17 \) \( 3-y: 5-3=4 \) \( 4.4+\sqrt{x}=-15 \) \( 5-y^{2}-8=56 \) \( 6 \cdot(x+4): 3=7 \) \( 7 \cdot 8+x-4=18 \) 8. \( 10+x, 6=52 \)
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
Let's solve each equation step by step.
1. **Equation:** \( 1 - (y - 8) = 2 \)
Rearranging gives:
\[
1 - y + 8 = 2 \implies 9 - y = 2 \implies y = 7
\]
2. **Equation:** \( 2 \cdot 3 \cdot x - 5 + 1 = 17 \)
Simplifying gives:
\[
6x - 5 + 1 = 17 \implies 6x - 4 = 17 \implies 6x = 21 \implies x = \frac{21}{6} = 3.5
\]
3. **Equation:** \( 3 - y = 5 - 3 \)
Simplifying gives:
\[
3 - y = 2 \implies -y = 2 - 3 \implies -y = -1 \implies y = 1
\]
4. **Equation:** \( 4.4 + \sqrt{x} = -15 \)
Rearranging gives:
\[
\sqrt{x} = -15 - 4.4 \implies \sqrt{x} = -19.4
\]
Since the square root cannot be negative, there is no solution for this equation.
5. **Equation:** \( 5 - y^2 - 8 = 56 \)
Rearranging gives:
\[
-y^2 - 3 = 56 \implies -y^2 = 59 \implies y^2 = -59
\]
Again, since \( y^2 \) cannot be negative, there is no solution for this equation.
6. **Equation:** \( 6 \cdot (x + 4) = 3 \cdot 7 \)
Simplifying gives:
\[
6(x + 4) = 21 \implies x + 4 = \frac{21}{6} \implies x + 4 = 3.5 \implies x = 3.5 - 4 = -0.5
\]
7. **Equation:** \( 7 \cdot 8 + x - 4 = 18 \)
Simplifying gives:
\[
56 + x - 4 = 18 \implies x + 52 = 18 \implies x = 18 - 52 = -34
\]
8. **Equation:** \( 10 + x = 6 \cdot 52 \)
Simplifying gives:
\[
10 + x = 312 \implies x = 312 - 10 = 302
\]
### Summary of Solutions:
1. \( y = 7 \)
2. \( x = 3.5 \)
3. \( y = 1 \)
4. No solution
5. No solution
6. \( x = -0.5 \)
7. \( x = -34 \)
8. \( x = 302 \)
Quick Answer
1. \( y = 7 \)
2. \( x = 3.5 \)
3. \( y = 1 \)
4. No solution
5. No solution
6. \( x = -0.5 \)
7. \( x = -34 \)
8. \( x = 302 \)
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