Which points are solutions to the equation \( y=3 x+5 \) ? Select all that apply. \( \square(-7,-16) \) \( \square(-3,-1) \) \( \square(-2,1) \) \( \square(7,16) \) \( \square(2,11) \) \( \square(7) \)

To determine which points are solutions to the equation \( y = 3x + 5 \), we will substitute the \( x \) values of each point into the equation and see if the resulting \( y \) value matches the \( y \) value of the point. 1. For the point \((-7, -16)\): \[ y = 3(-7) + 5 = -21 + 5 = -16 \] This point is a solution. 2. For the point \((-3, -1)\): \[ y = 3(-3) + 5 = -9 + 5 = -4 \] This point is not a solution. 3. For the point \((-2, 1)\): \[ y = 3(-2) + 5 = -6 + 5 = -1 \] This point is not a solution. 4. For the point \((7, 16)\): \[ y = 3(7) + 5 = 21 + 5 = 26 \] This point is not a solution. 5. For the point \((2, 11)\): \[ y = 3(2) + 5 = 6 + 5 = 11 \] This point is a solution. 6. The point \((7)\) is not a valid point since it does not have a \( y \) value. Thus, the points that are solutions to the equation \( y = 3x + 5 \) are: - \((-7, -16)\) - \((2, 11)\) So the final answer is: - \(\square(-7, -16)\) (solution) - \(\square(2, 11)\) (solution)