Weights of golden retriever dogs are normally distributed. Samples of weights of golden retriever dogs, each of size \( n=15 \), are randomly collected and the sample means are found. Is it correct to conclude that the sample means cannot be treated as being from a normal distribution because the sample size is too small? Explain. Choose the correct answer below. A. Yes; the sample size must be over 30 for the sample means to be normally distributed. B. No; the original population is normally distributed, so the sample means will be normally distributed for any sample size. C. No; as long as more than 30 samples are collected, the sample means will be normally distributed. D. No; the samples are collected randomly, so the sample means will be normally distributed for any sample size.

ISH The height of a fish compared to sea level as it jumps out of the ocean water can be represented by a function. Sketch a nonlinear 9 rimp hat shows the height of a fish \( y \), in inches, as a function of time \( x \), in seconds. Interpret the key features. Positive: between 2 seconds and 8 seconds Negative: for time less than 2 seconds and greater than 8 seconds Increasing: for time less than 5 seconds Decreasing: for time greater 5 seconds Relative Maximumi at 5 seconds, when the height of the fish is 9 inches End Behavion: As time increases or decreases, the height of the fish decreases. Symmetry: The height of the fish for time less than 5 seconds is the same as the height for time greater than 5 seconds.

1) \( \left(3 x^{n} y^{m}\right)^{2} \cdot\left(-2 x^{n} y^{m}\right)^{3} \)

Let \( f(x)^{\prime}=x^{3}-5 x^{2}+4 x-14 \). Find the following values. \( f^{\prime}(0)=4-14 \) \( f^{\prime}(2)=4 \)

I1 Points] DETAILS MY NOTES AUFQR2 4.2.P.002. PREVIOUS ANSWERS A business analyst deposited \( \$ 40,000 \) into an account earning an annual interest rate of \( 5.3 \% \) compounded monthly. If the analyst leaves the money in the account for 2 years, how much interest (in dollars) is earned on the account? (See Example 2 in this section. Round your answer to the nearest cent.) Enter a number. \( \$ \)

nla sustitución directa, en caso de que no se pueda encontrar, drán hallar el límite. \( \lim _{x \rightarrow 3}\left(-x^{3}+12 x^{2}+45 x-52\right) \) \( \lim _{x \rightarrow 3} \frac{x^{3}-9 x}{x^{2}-x-6} \) \( \lim _{x \rightarrow 4} \frac{4 x+16}{x^{2}-16} \) \( \lim _{x \rightarrow-2} \frac{x^{3}+8}{x+2} \) \( \lim _{x \rightarrow 7} \sqrt{3 x+4} \)