The overhead reach distances of adult females are normally distributed with a mean of 200 cm and a standard deviation of 8.9 cm. a. Find the probability that an individual distance is greater than 213.40 cm . b. Find the probability that the mean for 15 randomly selected distances is greater than 198.50 cm . c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30 ? 1

I1 Points] DETAILS MY NOTES AUFQR2 4.2.P.002. PREVIOUS ANSWERS A business analyst deposited \( \$ 40,000 \) into an account earning an annual interest rate of \( 5.3 \% \) compounded monthly. If the analyst leaves the money in the account for 2 years, how much interest (in dollars) is earned on the account? (See Example 2 in this section. Round your answer to the nearest cent.) Enter a number. \( \$ \)

If \( a=5 x-2 i \) and \( b=-4 x \), then find the value of the \( a b^{3} \) in fully simplified form.

8. \( -14.4=-0.6 p \) 2. \( 26=-\frac{8}{5} y \)

\( 1 \leftarrow \quad \) Fill in each blank so that the resulting statement is true. \( 4 x^{3}-36 x^{2}-88 x=\ldots\left(x^{2}-9 x-22\right)=\ldots(x+2)(x \), \( 4 x^{3}-36 x^{2}-88 x=\square\left(x^{2}-9 x-22\right)=\square(x+2)(x-11) \)

Which of the following statements about radical reactions is not true? Radicals rearrange. Breaking the weak O -O bond of peroxides initiates radical reactions. The diradical \( \mathrm{O}_{2} \) removes radicals from a reaction mixture. Light or heat provides the energy needed for homolytic bond cleavage to form radicals.