Stuart John
04/15/2024 · High School
The specific heat capacity of water is \( 4200 \mathrm{~J} /\left(\mathrm{kg}^{\circ} \mathrm{C}\right) \). The specific heat capacity of ice is \( 2100 \mathrm{~J} /\left(\mathrm{kg}^{\circ} \mathrm{C}\right) \). The specific latent heat of fusion of water is \( 3.3 \times 10^{5} \mathrm{~J} / \mathrm{kg} \). Calculate the energy given out as the water cools from \( 5.0^{\circ} \mathrm{C} \) to ice at \( -18.0^{\circ} \mathrm{C} \).
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The total energy given out is \( 384800m \, \mathrm{J} \), where \( m \) is the mass of the water in kilograms.
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