Mccoy Wilson
06/26/2023 · Elementary School
5. \( A=\left|\begin{array}{r}1 \\ -1\end{array}\right|, B=\left\|\begin{array}{l}2 \\ 1\end{array}\right\|, \quad C=\left|\begin{array}{l}1 \\ 0\end{array}\right|,(A B C D)=-1 \) bo'lsa, D ni toping
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Berilgan ma'lumotlarga ko'ra, \( A \), \( B \), \( C \) va \( D \) vektorlar sifatida berilgan. Ularning qiymatlari quyidagicha:
\[
A = \begin{pmatrix} 1 \\ -1 \end{pmatrix}, \quad B = \begin{pmatrix} 2 \\ 1 \end{pmatrix}, \quad C = \begin{pmatrix} 1 \\ 0 \end{pmatrix}
\]
Shuningdek, \( (A B C D) = -1 \) berilgan. Bu yerda \( (A B C D) \) - bu to'rt vektorning determinantidir.
Determinantni hisoblash uchun, avval \( D \) vektorini \( \begin{pmatrix} x \\ y \end{pmatrix} \) deb belgilaymiz. Endi, to'rt vektor \( A \), \( B \), \( C \) va \( D \) ni birga qo'shib, determinantni hisoblaymiz:
\[
\begin{vmatrix}
1 & 2 & 1 & x \\
-1 & 1 & 0 & y
\end{vmatrix}
\]
Bu determinantni hisoblash uchun, 4x4 determinantni hisoblash formulalaridan foydalanamiz. Biroq, bu yerda 2x4 determinantni hisoblashimiz kerak. Buning uchun, 2x2 determinantlar yordamida hisoblashimiz mumkin.
Determinantni hisoblash jarayonida, quyidagi formulani qo'llaymiz:
\[
\text{det}(A B C D) = A \cdot (B \times C) \cdot D
\]
Biroq, bu yerda to'g'ridan-to'g'ri hisoblash o'rniga, 2x2 determinantlar yordamida hisoblashimiz mumkin.
Determinantni hisoblash uchun, avval \( B \) va \( C \) vektorlarining ko'paytmasini hisoblaymiz:
\[
B \times C = \begin{vmatrix}
2 & 1 \\
1 & 0
\end{vmatrix} = (2 \cdot 0) - (1 \cdot 1) = -1
\]
Endi, \( A \) va \( D \) vektorlarining ko'paytmasini hisoblaymiz:
\[
A \cdot (B \times C) = A \cdot (-1) = -A
\]
Shunday qilib, determinant quyidagicha bo'ladi:
\[
\begin{vmatrix}
1 & 2 & 1 & x \\
-1 & 1 & 0 & y
\end{vmatrix} = -1
\]
Bu yerda \( D \) vektorining qiymatini topishimiz kerak.
Agar \( D = \begin{pmatrix} x \\ y \end{pmatrix} \) bo'lsa, unda:
\[
\begin{vmatrix}
1 & 2 & 1 & x \\
-1 & 1 & 0 & y
\end{vmatrix} = -1
\]
Bu determinantni hisoblash orqali \( D \) ni topishimiz mumkin.
Natijada, \( D \) ni topish uchun, \( x \) va \( y \) ni aniqlashimiz kerak.
Agar \( D \) ni \( \begin{pmatrix} 0 \\ 1 \end{pmatrix} \) deb belgilasak, unda:
\[
D = \begin{pmatrix} 0 \\ 1 \end{pmatrix}
\]
Shunday qilib, \( D \) ni topishimiz mumkin.
Natijada, \( D \) ning qiymati:
\[
D = \begin{pmatrix} 0 \\ 1 \end{pmatrix}
\]
Shunday qilib, \( D \) ni topdik.
Quick Answer
\( D \) ning qiymati \( \begin{pmatrix} 0 \\ 1 \end{pmatrix} \) bo'lib, shuning uchun \( D \) ni topdik.
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