MATHAdid The sum of interior angles of polygon is 198 Find the number of triangle the polyyon can subdivided inbo

To find the number of triangles a polygon can be subdivided into, we first need to determine the number of sides of the polygon using the formula for the sum of the interior angles of a polygon: \[ \text{Sum of interior angles} = (n - 2) \times 180 \] where \( n \) is the number of sides of the polygon. Given that the sum of the interior angles is 198 degrees, we can set up the equation: \[ (n - 2) \times 180 = 198 \] Now, we can solve for \( n \): 1. Divide both sides by 180: \[ n - 2 = \frac{198}{180} \] 2. Simplify the fraction: \[ n - 2 = \frac{11}{10} \] 3. Add 2 to both sides: \[ n = \frac{11}{10} + 2 = \frac{11}{10} + \frac{20}{10} = \frac{31}{10} \] Since \( n \) must be a whole number (as it represents the number of sides of a polygon), we see that there is no valid polygon with a sum of interior angles equal to 198 degrees. Thus, it is not possible to determine the number of triangles the polygon can be subdivided into, as the polygon itself does not exist with the given angle sum. If you have a different sum of interior angles or need further assistance, please let me know!