Hardy Schneider
09/04/2024 · Middle School

Use properties of logarithms to condense the loga expressions. \( \frac{1}{8}\left[3 \ln (x+5)-\ln x-\ln \left(x^{2}-36\right)\right] \) \( \frac{1}{8}\left[3 \ln (x+5)-\ln x-\ln \left(x^{2}-36\right)\right]=\square \) (Type an exact answer, using radicals as needed. T

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To condense the expression \[ \frac{1}{8}\left[3 \ln (x+5)-\ln x-\ln \left(x^{2}-36\right)\right], \] we can use the properties of logarithms. 1. **Use the power rule**: \( a \ln b = \ln(b^a) \) - For \( 3 \ln(x+5) \), we can rewrite it as \( \ln((x+5)^3) \). 2. **Use the quotient rule**: \( \ln a - \ln b = \ln\left(\frac{a}{b}\right) \) - We can combine \( -\ln x \) and \( -\ln(x^2 - 36) \) into a single logarithm. Now, let's rewrite the expression step by step: \[ 3 \ln(x+5) = \ln((x+5)^3) \] So, we have: \[ \frac{1}{8}\left[\ln((x+5)^3) - \ln x - \ln(x^2 - 36)\right] \] Next, we can combine the logarithms: \[ \ln((x+5)^3) - \ln x - \ln(x^2 - 36) = \ln\left(\frac{(x+5)^3}{x(x^2 - 36)}\right) \] Now, we can substitute this back into the expression: \[ \frac{1}{8} \ln\left(\frac{(x+5)^3}{x(x^2 - 36)}\right) \] Finally, we can use the power rule again to simplify: \[ \frac{1}{8} \ln\left(\frac{(x+5)^3}{x(x^2 - 36)}\right) = \ln\left(\left(\frac{(x+5)^3}{x(x^2 - 36)}\right)^{\frac{1}{8}}\right) \] Thus, the condensed expression is: \[ \ln\left(\left(\frac{(x+5)^3}{x(x^2 - 36)}\right)^{\frac{1}{8}}\right) \] So the final answer is: \[ \ln\left(\frac{(x+5)^{\frac{3}{8}}}{x^{\frac{1}{8}}(x^2 - 36)^{\frac{1}{8}}}\right) \]

Quick Answer

\[ \ln\left(\frac{(x+5)^{\frac{3}{8}}}{x^{\frac{1}{8}}(x^2 - 36)^{\frac{1}{8}}}\right) \]
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