Warren Wheeler
04/22/2024 · Middle School
\( \begin{array}{lll}= & 1.4^{x} & 8 \cdot\left(\frac{2}{3}\right)^{x} \\ 2.6^{x} & 9 \cdot\left(\frac{1}{5}\right)^{x} \\ 3.3^{x} & 10 \cdot\left(\frac{3}{7}\right)^{x} \\ 4.7^{x} & \\ = & 5.5^{x} & \\ = & 6 .\left(\frac{1}{4}\right)^{x} & \text { Desarrollar } \\ 7 .\left(\frac{2}{5}\right)^{x} & \end{array} \)
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Para resolver la ecuación dada, se analizan cada una de las igualdades y se simplifican. Se divide cada lado de las ecuaciones por la base correspondiente y se toma el logaritmo para encontrar la solución de \( x \).
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