Harrington Frank
11/15/2023 · Primary School
There is function \( f(x)=\frac{2 x-1}{x}+1 \quad \) s 5 fing \( f(2) \times f(0) \)
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Step-by-step Solution
To find \( f(2) \times f(0) \) for the function \( f(x) = \frac{2x - 1}{x} + 1 \), we first need to calculate \( f(2) \) and \( f(0) \).
1. **Calculate \( f(2) \)**:
\[
f(2) = \frac{2(2) - 1}{2} + 1 = \frac{4 - 1}{2} + 1 = \frac{3}{2} + 1 = \frac{3}{2} + \frac{2}{2} = \frac{5}{2}
\]
2. **Calculate \( f(0) \)**:
\[
f(0) = \frac{2(0) - 1}{0} + 1
\]
The term \( \frac{2(0) - 1}{0} \) is undefined because we cannot divide by zero. Therefore, \( f(0) \) is undefined.
Since \( f(0) \) is undefined, the product \( f(2) \times f(0) \) is also undefined.
Thus, the final answer is:
\[
\text{undefined}
\]
Quick Answer
The product \( f(2) \times f(0) \) is undefined.
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