Malone Gray

01/27/2024 · Primary School

When an object is thrown upward, its height ( S ), in meters, is given (approximately) by the quadratic equation \( \mathrm{S}=-5 \mathrm{t}^{2}+\mathrm{vt}+\mathrm{h} \), where \( v \) is the upward initial velocity in meters/second, t is the time of flight in seconds, and h is the height above level ground from which the object is thrown. Johnny is standing on a platform 16 meters high and throws a ball straight up as high as he can at a velocity of 16 meters/second. At what time \( t \) will the ball hit the ground? How far from the ground is the ball after 3 seconds have elapsed from the time of the throw? (Assume that the ball is 16 meters from the ground when it leaves Johnny's hand.)