Trabajo Práctico Evaluativo 1) Resuelve las siguientes ecuaciones, \( y \) verifica el resultado. a) \( -60+4=7 \cdot(\mathrm{a}-4) \) b) \( (2 \cdot \mathrm{b}-3) \cdot 4=12 \) c) \( (15 \cdot \mathrm{x}+10): 5=8 \)

Solve the equation \( -60+4=7*(a-4) \). Solve the equation by following steps: - step0: Solve for \(a\): \(-60+4=7\left(a-4\right)\) - step1: Add the numbers: \(-56=7\left(a-4\right)\) - step2: Swap the sides: \(7\left(a-4\right)=-56\) - step3: Divide both sides: \(\frac{7\left(a-4\right)}{7}=\frac{-56}{7}\) - step4: Divide the numbers: \(a-4=-8\) - step5: Move the constant to the right side: \(a=-8+4\) - step6: Add the numbers: \(a=-4\) Solve the equation \( (2*b-3)*4=12 \). Solve the equation by following steps: - step0: Solve for \(b\): \(\left(2b-3\right)\times 4=12\) - step1: Multiply the terms: \(4\left(2b-3\right)=12\) - step2: Divide both sides: \(\frac{4\left(2b-3\right)}{4}=\frac{12}{4}\) - step3: Divide the numbers: \(2b-3=3\) - step4: Move the constant to the right side: \(2b=3+3\) - step5: Add the numbers: \(2b=6\) - step6: Divide both sides: \(\frac{2b}{2}=\frac{6}{2}\) - step7: Divide the numbers: \(b=3\) Solve the equation \( (15*x+10)/5=8 \). Solve the equation by following steps: - step0: Solve for \(x\): \(\frac{\left(15x+10\right)}{5}=8\) - step1: Remove the parentheses: \(\frac{15x+10}{5}=8\) - step2: Divide the terms: \(3x+2=8\) - step3: Move the constant to the right side: \(3x=8-2\) - step4: Subtract the numbers: \(3x=6\) - step5: Divide both sides: \(\frac{3x}{3}=\frac{6}{3}\) - step6: Divide the numbers: \(x=2\) a) La solución de la ecuación \( -60+4=7(a-4) \) es \( a=-4 \). b) La solución de la ecuación \( (2b-3)\cdot4=12 \) es \( b=3 \). c) La solución de la ecuación \( (15x+10)/5=8 \) es \( x=2 \).