Cole Lowe
07/05/2023 · Primary School
\( (\sqrt{6},-\sqrt{2}) \) une expression.) \( \cos \alpha=\frac{\sqrt{3}}{2} \) (Simplify your answer. Type an exact answer, using radicals as needed. Use integers or fractions for the expression.) tan \( \alpha=\square \) (Simplify your answer. Type an exact answer, using radicals as needed. Use integers or fractions for the expression.)
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- In the first quadrant: \(\tan \alpha = \frac{\sqrt{3}}{3}\)
- In the fourth quadrant: \(\tan \alpha = -\frac{\sqrt{3}}{3}\)
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