Carroll Valdez
12/20/2023 · High School

2) \( \begin{array}{l} A=\{a, e, i\} \\ B=\{0, u\} \\ \text { Resuelve : } a x b=? \\ B x a=?\end{array} \)

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Para resolver los productos cartesianos \( A \times B \) y \( B \times A \), seguimos la definición del producto cartesiano, que consiste en formar pares ordenados donde el primer elemento proviene del primer conjunto y el segundo elemento proviene del segundo conjunto. 1. **Calcular \( A \times B \)**: - \( A = \{a, e, i\} \) - \( B = \{0, u\} \) Los pares ordenados se forman combinando cada elemento de \( A \) con cada elemento de \( B \): \[ A \times B = \{(a, 0), (a, u), (e, 0), (e, u), (i, 0), (i, u)\} \] 2. **Calcular \( B \times A \)**: - \( B = \{0, u\} \) - \( A = \{a, e, i\} \) De manera similar, formamos los pares ordenados combinando cada elemento de \( B \) con cada elemento de \( A \): \[ B \times A = \{(0, a), (0, e), (0, i), (u, a), (u, e), (u, i)\} \] Por lo tanto, los resultados son: - \( A \times B = \{(a, 0), (a, u), (e, 0), (e, u), (i, 0), (i, u)\} \) - \( B \times A = \{(0, a), (0, e), (0, i), (u, a), (u, e), (u, i)\} \)

Quick Answer

- \( A \times B = \{(a, 0), (a, u), (e, 0), (e, u), (i, 0), (i, u)\} \) - \( B \times A = \{(0, a), (0, e), (0, i), (u, a), (u, e), (u, i)\} \)
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