Hobbs O'Quinn
05/31/2023 · Junior High School
5. Quyidagi to'g'ri chiziqlarning o'zaro vaziyatini aniqlang: \( \left\{\begin{array}{c}x-2 y+3 z+4=0 \\ x+2 y-5 z+1=0\end{array}\right. \) va \( \left\{\begin{array}{c}x+y+z+1=0 \\ y-3 z=0\end{array}\right. \)
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Berilgan to'g'ri chiziqlarni aniqlash uchun, har bir to'g'ri chiziqning parametrik tenglamalarini yozamiz va ularning o'zaro vaziyatini tahlil qilamiz.
1. **Birinchi to'g'ri chiziq:**
\[
\begin{cases}
x - 2y + 3z + 4 = 0 \\
x + 2y - 5z + 1 = 0
\end{cases}
\]
Bu tenglamalarni yechamiz. Birinchi tenglamadan \( x \) ni ifodalash:
\[
x = 2y - 3z - 4
\]
Ikkinchi tenglamaga qo'yamiz:
\[
(2y - 3z - 4) + 2y - 5z + 1 = 0
\]
\[
4y - 8z - 3 = 0
\]
\[
4y = 8z + 3 \quad \Rightarrow \quad y = 2z + \frac{3}{4}
\]
Endi \( y \) ni \( z \) ga bog'lab, \( x \) ni ifodalashimiz mumkin:
\[
x = 2(2z + \frac{3}{4}) - 3z - 4
\]
\[
x = 4z + \frac{3}{2} - 3z - 4 = z - \frac{5}{2}
\]
Natijada, birinchi to'g'ri chiziqning parametrik tenglamalari:
\[
\begin{cases}
x = z - \frac{5}{2} \\
y = 2z + \frac{3}{4} \\
z = z
\end{cases}
\]
Bu yerda \( z \) parametr sifatida olinadi.
2. **Ikkinchi to'g'ri chiziq:**
\[
\begin{cases}
x + y + z + 1 = 0 \\
y - 3z = 0
\end{cases}
\]
Ikkinchi tenglamadan \( y \) ni ifodalash:
\[
y = 3z
\]
Birinchi tenglamaga qo'yamiz:
\[
x + 3z + z + 1 = 0
\]
\[
x + 4z + 1 = 0 \quad \Rightarrow \quad x = -4z - 1
\]
Natijada, ikkinchi to'g'ri chiziqning parametrik tenglamalari:
\[
\begin{cases}
x = -4z - 1 \\
y = 3z \\
z = z
\end{cases}
\]
3. **O'zaro vaziyatni aniqlash:**
Har ikkala to'g'ri chiziqning parametrik tenglamalarini ko'rib chiqamiz:
- Birinchi to'g'ri chiziq:
\[
\begin{cases}
x = z - \frac{5}{2} \\
y = 2z + \frac{3}{4} \\
z = z
\end{cases}
\]
- Ikkinchi to'g'ri chiziq:
\[
\begin{cases}
x = -4z - 1 \\
y = 3z \\
z = z
\end{cases}
\]
Har ikkala to'g'ri chiziqning tenglamalarini tenglashtiramiz:
\[
z - \frac{5}{2} = -4z - 1 \quad \Rightarrow \quad 5z = \frac{3}{2} \quad \Rightarrow \quad z = \frac{3}{10}
\]
\( z \) ni topgach, \( y \) va \( x \) ni hisoblaymiz:
- Birinchi to'g'ri chiziqdan:
\[
y = 2 \cdot \frac{3}{10} + \frac{3}{4} = \frac{6}{10} + \frac{30}{40} = \frac{6}{10} + \frac{15}{20} = \frac{6 + 15}{
Quick Answer
Birinchi to'g'ri chiziq va ikkinchi to'g'ri chiziq o'zaro kesishadi.
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