Salazar Mullins

04/08/2023 · Elementary School

In a laboratory setup, a block of ice of mass mi at an initial temperature of \( -15^{\circ} \mathrm{C} \) is needed to transform 0.5 kg of steam contained in a sealed glass container from \( 110^{\circ} \mathrm{C} \) into water at \( 15^{\circ} \mathrm{C} \). The specific heat capacity of ice, \( \underline{\text { water and }} \) steam are respectively \( \mathrm{Ci}=2090 \mathrm{~J} / \mathrm{kg}^{\circ} \mathrm{C}, \mathrm{Cw}=4186 \mathrm{~J} / \mathrm{kg}{ }^{\circ} \mathrm{C} \) and \( \mathrm{Cs}=2010 \mathrm{~J} / \mathrm{kg}^{\circ} \mathrm{C} \), the steam and the glass container are in thermal equilibrium Fusion point of water (or melting point of ice) \( 0^{\circ} \mathrm{C} \) Vaporization point of water \( 100^{\circ} \mathrm{C} \) The latent heat of condensation steam Lc= \( 2.26 \times 10^{\wedge} 6 \mathrm{~J} / \mathrm{kg} \) Latent heat of Fusion of ice \( \mathrm{Lf}=3.36 \times 10^{\wedge} 5 \mathrm{~J} / \) kg The amount of heat Qg gained during the