Find the length of AB to the nearest tenth of a metre. Hint: using \(\triangle A C D\) , find the length of \(A C\) (tan) using \(\triangle B C D\) , find the length of \(B C\) (tan) subtract \(A C - B C\) to find the length of \(A B\)
Question
Answer
AB = AC - BC = 80.4-23.9 = 56.5 m
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