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Morrison Bush
07/02/2023 · escuela secundaria
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
The following is a 3-step proof. Complete the proof.
Given: \( \angle 1 = \angle 2 \)
\( A P = B P\)
Prove: \( \triangle A P D \cong \triangle B P C\)
\( \angle 1 = \angle 2 \)
\( AP = BP \)
\( \angle APD = \angle BPC \)
\( APD \cong \triangle BPC\)
Find the equation of the sphere passing through\( P ( - 6,5,4 ) \)and\( Q ( 2 , - 7,5 ) \)with its center at the midpoint of\( P Q \).
The standard equation of the sphere is
(Simplify your answer.)
Identify the intervals over which the function is increasing.
Solve\( 9 \cos ( 2 w ) = 9 \sin ^ { 2 } ( w ) + 3 \)for all solutions\( 0 \leq w < 2 \pi \)
\( w = \)
Give your answers accurate to at least 2 decimal places, as a list separated by commas
Graph the following function.
\( y = - 4 ( x - 1 ) ^ { 2 } - 5\)
Use the Law of Sines to solve for the remaining side(s) and angle(s) of all triangles if
\( \beta = 113 ^ { \circ } , b = 14.25 , c = 11.25 \). Round to two decimal places.
As in the text,\( ( \alpha , a ) , ( \beta , b ) \)and\( ( \gamma , c ) \)are angle-side opposite pairs. If no such triangle exists, enter DNE in each answer box.
Enter the values for an acute triangle solution:
\( \gamma = \square \)degrees
\( \alpha = \square \)degrees
\( a = \square \)degrees
Enter the values for an obtuse triangle solution:
\( \gamma ^ { \prime } = \square \)degrees
\( \alpha ^ { \prime } = \square \)degrees
\( a ^ { \prime } = \square \)degrees
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