\(\frac{22±\sqrt{411} }{4}\)
\(\frac{22+ \sqrt{493} }{4}\)
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Valdez Robbins
07/03/2020 · Elementary School
An object is thrown upward at a speed of \( 176 \) feet per second by a machine from a height of \( 9 \) feet off the ground. The height \( h \) of the object after \( t \) seconds can be found using the equation \( h = - 16 t ^ { 2 } + 176 t + 9 \) When will the height be \( 82 \) feet? When will the object reach the ground?
\(\frac{22±\sqrt{411} }{4}\)
\(\frac{22+ \sqrt{493} }{4}\)
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