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Question
x^{2}-11x+24
Factor the expression
\left(x-8\right)\left(x-3\right)
Evaluate
x^{2}-11x+24
Rewrite the expression
x^{2}+\left(-3-8\right)x+24
Calculate
x^{2}-3x-8x+24
Rewrite the expression
x\times x-x\times 3-8x+8\times 3
\text{Factor out }x\text{ from the expression}
x\left(x-3\right)-8x+8\times 3
\text{Factor out }-8\text{ from the expression}
x\left(x-3\right)-8\left(x-3\right)
Solution
\left(x-8\right)\left(x-3\right)
Show Solutions
Find the roots
x_{1}=3,x_{2}=8
Evaluate
x^{2}-11x+24
To find the roots of the expression,set the expression equal to 0
x^{2}-11x+24=0
Factor the expression
More Steps
Evaluate
x^{2}-11x+24
Rewrite the expression
x^{2}+\left(-3-8\right)x+24
Calculate
x^{2}-3x-8x+24
Rewrite the expression
x\times x-x\times 3-8x+8\times 3
\text{Factor out }x\text{ from the expression}
x\left(x-3\right)-8x+8\times 3
\text{Factor out }-8\text{ from the expression}
x\left(x-3\right)-8\left(x-3\right)
\text{Factor out }x-3\text{ from the expression}
\left(x-8\right)\left(x-3\right)
\left(x-8\right)\left(x-3\right)=0
When the product of factors equals 0,at least one factor is 0
\begin{align}&x-8=0\\&x-3=0\end{align}
\text{Solve the equation for }x
More Steps
Evaluate
x-8=0
Move the constant to the right-hand side and change its sign
x=0+8
Removing 0 doesn't change the value,so remove it from the expression
x=8
\begin{align}&x=8\\&x-3=0\end{align}
\text{Solve the equation for }x
More Steps
Evaluate
x-3=0
Move the constant to the right-hand side and change its sign
x=0+3
Removing 0 doesn't change the value,so remove it from the expression
x=3
\begin{align}&x=8\\&x=3\end{align}
Solution
x_{1}=3,x_{2}=8
Show Solutions
