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Question
x^{2}-16x+48
Factor the expression
\left(x-12\right)\left(x-4\right)
Evaluate
x^{2}-16x+48
Rewrite the expression
x^{2}+\left(-4-12\right)x+48
Calculate
x^{2}-4x-12x+48
Rewrite the expression
x\times x-x\times 4-12x+12\times 4
\text{Factor out }x\text{ from the expression}
x\left(x-4\right)-12x+12\times 4
\text{Factor out }-12\text{ from the expression}
x\left(x-4\right)-12\left(x-4\right)
Solution
\left(x-12\right)\left(x-4\right)
Show Solutions
Find the roots
x_{1}=4,x_{2}=12
Evaluate
x^{2}-16x+48
To find the roots of the expression,set the expression equal to 0
x^{2}-16x+48=0
Factor the expression
More Steps
Evaluate
x^{2}-16x+48
Rewrite the expression
x^{2}+\left(-4-12\right)x+48
Calculate
x^{2}-4x-12x+48
Rewrite the expression
x\times x-x\times 4-12x+12\times 4
\text{Factor out }x\text{ from the expression}
x\left(x-4\right)-12x+12\times 4
\text{Factor out }-12\text{ from the expression}
x\left(x-4\right)-12\left(x-4\right)
\text{Factor out }x-4\text{ from the expression}
\left(x-12\right)\left(x-4\right)
\left(x-12\right)\left(x-4\right)=0
When the product of factors equals 0,at least one factor is 0
\begin{align}&x-12=0\\&x-4=0\end{align}
\text{Solve the equation for }x
More Steps
Evaluate
x-12=0
Move the constant to the right-hand side and change its sign
x=0+12
Removing 0 doesn't change the value,so remove it from the expression
x=12
\begin{align}&x=12\\&x-4=0\end{align}
\text{Solve the equation for }x
More Steps
Evaluate
x-4=0
Move the constant to the right-hand side and change its sign
x=0+4
Removing 0 doesn't change the value,so remove it from the expression
x=4
\begin{align}&x=12\\&x=4\end{align}
Solution
x_{1}=4,x_{2}=12
Show Solutions
