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Question

t^{2}\times 8-1
Simplify the expression
8t^{2}-1
Evaluate
t^{2}\times 8-1
Solution
8t^{2}-1
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Find the roots
t_{1}=-\frac{\sqrt{2}}{4},t_{2}=\frac{\sqrt{2}}{4}
Alternative Form
t_{1}\approx -0.353553,t_{2}\approx 0.353553
Evaluate
t^{2}\times 8-1
To find the roots of the expression,set the expression equal to 0
t^{2}\times 8-1=0
Use the commutative property to reorder the terms
8t^{2}-1=0
Move the constant to the right-hand side and change its sign
8t^{2}=0+1
Removing 0 doesn't change the value,so remove it from the expression
8t^{2}=1
Divide both sides
\frac{8t^{2}}{8}=\frac{1}{8}
Divide the numbers
t^{2}=\frac{1}{8}
Take the root of both sides of the equation and remember to use both positive and negative roots
t=\pm \sqrt{\frac{1}{8}}
Simplify the expression
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Evaluate
\sqrt{\frac{1}{8}}
To take a root of a fraction,take the root of the numerator and denominator separately
\frac{\sqrt{1}}{\sqrt{8}}
Simplify the radical expression
\frac{1}{\sqrt{8}}
Simplify the radical expression
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Evaluate
\sqrt{8}
Write the expression as a product where the root of one of the factors can be evaluated
\sqrt{4\times 2}
\text{Write the number in exponential form with the base of }2
\sqrt{2^{2}\times 2}
The root of a product is equal to the product of the roots of each factor
\sqrt{2^{2}}\times \sqrt{2}
\text{Reduce the index of the radical and exponent with }2
2\sqrt{2}
\frac{1}{2\sqrt{2}}
Multiply by the Conjugate
\frac{\sqrt{2}}{2\sqrt{2}\times \sqrt{2}}
Multiply the numbers
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Evaluate
2\sqrt{2}\times \sqrt{2}
When a square root of an expression is multiplied by itself,the result is that expression
2\times 2
Multiply the numbers
4
\frac{\sqrt{2}}{4}
t=\pm \frac{\sqrt{2}}{4}
\text{Separate the equation into }2\text{ possible cases}
\begin{align}&t=\frac{\sqrt{2}}{4}\\&t=-\frac{\sqrt{2}}{4}\end{align}
Solution
t_{1}=-\frac{\sqrt{2}}{4},t_{2}=\frac{\sqrt{2}}{4}
Alternative Form
t_{1}\approx -0.353553,t_{2}\approx 0.353553
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