Type a math problem or upload a photo, screenshot, handwritten question...
error msg
- Algebra
- Calculus
- Trigonometry
- Matrix
- Differential
- Integral
- Trigonometry
- Letters
Question
p^{4}\times 6802-1
Simplify the expression
6802p^{4}-1
Evaluate
p^{4}\times 6802-1
Solution
6802p^{4}-1
Show Solutions
Find the roots
p_{1}=-\frac{\sqrt[4]{6802^{3}}}{6802},p_{2}=\frac{\sqrt[4]{6802^{3}}}{6802}
Alternative Form
p_{1}\approx -0.110114,p_{2}\approx 0.110114
Evaluate
p^{4}\times 6802-1
To find the roots of the expression,set the expression equal to 0
p^{4}\times 6802-1=0
Use the commutative property to reorder the terms
6802p^{4}-1=0
Move the constant to the right-hand side and change its sign
6802p^{4}=0+1
Removing 0 doesn't change the value,so remove it from the expression
6802p^{4}=1
Divide both sides
\frac{6802p^{4}}{6802}=\frac{1}{6802}
Divide the numbers
p^{4}=\frac{1}{6802}
Take the root of both sides of the equation and remember to use both positive and negative roots
p=\pm \sqrt[4]{\frac{1}{6802}}
Simplify the expression
More Steps
Evaluate
\sqrt[4]{\frac{1}{6802}}
To take a root of a fraction,take the root of the numerator and denominator separately
\frac{\sqrt[4]{1}}{\sqrt[4]{6802}}
Simplify the radical expression
\frac{1}{\sqrt[4]{6802}}
Multiply by the Conjugate
\frac{\sqrt[4]{6802^{3}}}{\sqrt[4]{6802}\times \sqrt[4]{6802^{3}}}
Multiply the numbers
More Steps
Evaluate
\sqrt[4]{6802}\times \sqrt[4]{6802^{3}}
The product of roots with the same index is equal to the root of the product
\sqrt[4]{6802\times 6802^{3}}
Calculate the product
\sqrt[4]{6802^{4}}
\text{Reduce the index of the radical and exponent with }4
6802
\frac{\sqrt[4]{6802^{3}}}{6802}
p=\pm \frac{\sqrt[4]{6802^{3}}}{6802}
\text{Separate the equation into }2\text{ possible cases}
\begin{align}&p=\frac{\sqrt[4]{6802^{3}}}{6802}\\&p=-\frac{\sqrt[4]{6802^{3}}}{6802}\end{align}
Solution
p_{1}=-\frac{\sqrt[4]{6802^{3}}}{6802},p_{2}=\frac{\sqrt[4]{6802^{3}}}{6802}
Alternative Form
p_{1}\approx -0.110114,p_{2}\approx 0.110114
Show Solutions
