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Question
p^{2}\times 8354-1
Simplify the expression
8354p^{2}-1
Evaluate
p^{2}\times 8354-1
Solution
8354p^{2}-1
Show Solutions
Find the roots
p_{1}=-\frac{\sqrt{8354}}{8354},p_{2}=\frac{\sqrt{8354}}{8354}
Alternative Form
p_{1}\approx -0.010941,p_{2}\approx 0.010941
Evaluate
p^{2}\times 8354-1
To find the roots of the expression,set the expression equal to 0
p^{2}\times 8354-1=0
Use the commutative property to reorder the terms
8354p^{2}-1=0
Move the constant to the right-hand side and change its sign
8354p^{2}=0+1
Removing 0 doesn't change the value,so remove it from the expression
8354p^{2}=1
Divide both sides
\frac{8354p^{2}}{8354}=\frac{1}{8354}
Divide the numbers
p^{2}=\frac{1}{8354}
Take the root of both sides of the equation and remember to use both positive and negative roots
p=\pm \sqrt{\frac{1}{8354}}
Simplify the expression
More Steps
Evaluate
\sqrt{\frac{1}{8354}}
To take a root of a fraction,take the root of the numerator and denominator separately
\frac{\sqrt{1}}{\sqrt{8354}}
Simplify the radical expression
\frac{1}{\sqrt{8354}}
Multiply by the Conjugate
\frac{\sqrt{8354}}{\sqrt{8354}\times \sqrt{8354}}
When a square root of an expression is multiplied by itself,the result is that expression
\frac{\sqrt{8354}}{8354}
p=\pm \frac{\sqrt{8354}}{8354}
\text{Separate the equation into }2\text{ possible cases}
\begin{align}&p=\frac{\sqrt{8354}}{8354}\\&p=-\frac{\sqrt{8354}}{8354}\end{align}
Solution
p_{1}=-\frac{\sqrt{8354}}{8354},p_{2}=\frac{\sqrt{8354}}{8354}
Alternative Form
p_{1}\approx -0.010941,p_{2}\approx 0.010941
Show Solutions
