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Question
h^{4}-2=2
Solve the equation
h_{1}=-\sqrt{2},h_{2}=\sqrt{2}
Alternative Form
h_{1}\approx -1.414214,h_{2}\approx 1.414214
Evaluate
h^{4}-2=2
Move the constant to the right-hand side and change its sign
h^{4}=2+2
Add the numbers
h^{4}=4
Take the root of both sides of the equation and remember to use both positive and negative roots
h=\pm \sqrt[4]{4}
Simplify the expression
More Steps
Evaluate
\sqrt[4]{4}
\text{Write the number in exponential form with the base of }2
\sqrt[4]{2^{2}}
\text{Reduce the index of the radical and exponent with }2
\sqrt{2}
h=\pm \sqrt{2}
\text{Separate the equation into }2\text{ possible cases}
\begin{align}&h=\sqrt{2}\\&h=-\sqrt{2}\end{align}
Solution
h_{1}=-\sqrt{2},h_{2}=\sqrt{2}
Alternative Form
h_{1}\approx -1.414214,h_{2}\approx 1.414214
Show Solutions
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