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Question
e^{2x}-1
Factor the expression
\left(e^{x}-1\right)\left(e^{x}+1\right)
Evaluate
e^{2x}-1
Evaluate
\left(e^{x}\right)^{2}-1
Solution
\left(e^{x}-1\right)\left(e^{x}+1\right)
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Find the roots
x=0
Evaluate
e^{2x}-1
To find the roots of the expression,set the expression equal to 0
e^{2x}-1=0
Move the constant to the right-hand side and change its sign
e^{2x}=0+1
Removing 0 doesn't change the value,so remove it from the expression
e^{2x}=1
\text{Write the number in exponential form with the base of }e
e^{2x}=e^{0}
Since the bases are the same,set the exponents equal
2x=0
Solution
x=0
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