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Question

8x\times 8-6x^{6}
Simplify the expression
64x-6x^{6}
Evaluate
8x\times 8-6x^{6}
Solution
64x-6x^{6}
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Factor the expression
2x\left(32-3x^{5}\right)
Evaluate
8x\times 8-6x^{6}
Multiply the terms
64x-6x^{6}
Rewrite the expression
2x\times 32-2x\times 3x^{5}
Solution
2x\left(32-3x^{5}\right)
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Find the roots
x_{1}=0,x_{2}=\frac{2\sqrt[5]{81}}{3}
Alternative Form
x_{1}=0,x_{2}\approx 1.605483
Evaluate
8x\times 8-6x^{6}
To find the roots of the expression,set the expression equal to 0
8x\times 8-6x^{6}=0
Multiply the terms
64x-6x^{6}=0
Factor the expression
2x\left(32-3x^{5}\right)=0
Divide both sides
x\left(32-3x^{5}\right)=0
\text{Separate the equation into }2\text{ possible cases}
\begin{align}&x=0\\&32-3x^{5}=0\end{align}
Solve the equation
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Evaluate
32-3x^{5}=0
Move the constant to the right-hand side and change its sign
-3x^{5}=0-32
Removing 0 doesn't change the value,so remove it from the expression
-3x^{5}=-32
Change the signs on both sides of the equation
3x^{5}=32
Divide both sides
\frac{3x^{5}}{3}=\frac{32}{3}
Divide the numbers
x^{5}=\frac{32}{3}
\text{Take the }5\text{-th root on both sides of the equation}
\sqrt[5]{x^{5}}=\sqrt[5]{\frac{32}{3}}
Calculate
x=\sqrt[5]{\frac{32}{3}}
Simplify the root
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Evaluate
\sqrt[5]{\frac{32}{3}}
To take a root of a fraction,take the root of the numerator and denominator separately
\frac{\sqrt[5]{32}}{\sqrt[5]{3}}
Simplify the radical expression
\frac{2}{\sqrt[5]{3}}
Multiply by the Conjugate
\frac{2\sqrt[5]{3^{4}}}{\sqrt[5]{3}\times \sqrt[5]{3^{4}}}
Simplify
\frac{2\sqrt[5]{81}}{\sqrt[5]{3}\times \sqrt[5]{3^{4}}}
Multiply the numbers
\frac{2\sqrt[5]{81}}{3}
x=\frac{2\sqrt[5]{81}}{3}
\begin{align}&x=0\\&x=\frac{2\sqrt[5]{81}}{3}\end{align}
Solution
x_{1}=0,x_{2}=\frac{2\sqrt[5]{81}}{3}
Alternative Form
x_{1}=0,x_{2}\approx 1.605483
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