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Question
5x^{2}\times 9=10x\times 1
Solve the quadratic equation
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Solve by factoring
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Solve using the quadratic formula
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Solve by completing the square
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Solve using the PQ formula
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x_{1}=0,x_{2}=\frac{2}{9}
Alternative Form
x_{1}=0,x_{2}=0.\dot{2}
Evaluate
5x^{2}\times 9=10x\times 1
Multiply the terms
45x^{2}=10x\times 1
Multiply the terms
45x^{2}=10x
Move the expression to the left side
45x^{2}-10x=0
Factor the expression
More Steps
Evaluate
45x^{2}-10x
Rewrite the expression
5x\times 9x-5x\times 2
\text{Factor out }5x\text{ from the expression}
5x\left(9x-2\right)
5x\left(9x-2\right)=0
When the product of factors equals 0,at least one factor is 0
\begin{align}&9x-2=0\\&5x=0\end{align}
\text{Solve the equation for }x
More Steps
Evaluate
9x-2=0
Move the constant to the right-hand side and change its sign
9x=0+2
Removing 0 doesn't change the value,so remove it from the expression
9x=2
Divide both sides
\frac{9x}{9}=\frac{2}{9}
Divide the numbers
x=\frac{2}{9}
\begin{align}&x=\frac{2}{9}\\&5x=0\end{align}
\text{Solve the equation for }x
\begin{align}&x=\frac{2}{9}\\&x=0\end{align}
Solution
x_{1}=0,x_{2}=\frac{2}{9}
Alternative Form
x_{1}=0,x_{2}=0.\dot{2}
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