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Question
3x-8x^{4}
Factor the expression
x\left(3-8x^{3}\right)
Evaluate
3x-8x^{4}
Rewrite the expression
x\times 3-x\times 8x^{3}
Solution
x\left(3-8x^{3}\right)
Show Solutions
Find the roots
x_{1}=0,x_{2}=\frac{\sqrt[3]{3}}{2}
Alternative Form
x_{1}=0,x_{2}\approx 0.721125
Evaluate
3x-8x^{4}
To find the roots of the expression,set the expression equal to 0
3x-8x^{4}=0
Factor the expression
x\left(3-8x^{3}\right)=0
\text{Separate the equation into }2\text{ possible cases}
\begin{align}&x=0\\&3-8x^{3}=0\end{align}
Solve the equation
More Steps
Evaluate
3-8x^{3}=0
Move the constant to the right-hand side and change its sign
-8x^{3}=0-3
Removing 0 doesn't change the value,so remove it from the expression
-8x^{3}=-3
Change the signs on both sides of the equation
8x^{3}=3
Divide both sides
\frac{8x^{3}}{8}=\frac{3}{8}
Divide the numbers
x^{3}=\frac{3}{8}
\text{Take the }3\text{-th root on both sides of the equation}
\sqrt[3]{x^{3}}=\sqrt[3]{\frac{3}{8}}
Calculate
x=\sqrt[3]{\frac{3}{8}}
Simplify the root
More Steps
Evaluate
\sqrt[3]{\frac{3}{8}}
To take a root of a fraction,take the root of the numerator and denominator separately
\frac{\sqrt[3]{3}}{\sqrt[3]{8}}
Simplify the radical expression
\frac{\sqrt[3]{3}}{2}
x=\frac{\sqrt[3]{3}}{2}
\begin{align}&x=0\\&x=\frac{\sqrt[3]{3}}{2}\end{align}
Solution
x_{1}=0,x_{2}=\frac{\sqrt[3]{3}}{2}
Alternative Form
x_{1}=0,x_{2}\approx 0.721125
Show Solutions
