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Question
2x-33x^{3}
Factor the expression
x\left(2-33x^{2}\right)
Evaluate
2x-33x^{3}
Rewrite the expression
x\times 2-x\times 33x^{2}
Solution
x\left(2-33x^{2}\right)
Show Solutions
Find the roots
x_{1}=-\frac{\sqrt{66}}{33},x_{2}=0,x_{3}=\frac{\sqrt{66}}{33}
Alternative Form
x_{1}\approx -0.246183,x_{2}=0,x_{3}\approx 0.246183
Evaluate
2x-33x^{3}
To find the roots of the expression,set the expression equal to 0
2x-33x^{3}=0
Factor the expression
x\left(2-33x^{2}\right)=0
\text{Separate the equation into }2\text{ possible cases}
\begin{align}&x=0\\&2-33x^{2}=0\end{align}
Solve the equation
More Steps
Evaluate
2-33x^{2}=0
Move the constant to the right-hand side and change its sign
-33x^{2}=0-2
Removing 0 doesn't change the value,so remove it from the expression
-33x^{2}=-2
Change the signs on both sides of the equation
33x^{2}=2
Divide both sides
\frac{33x^{2}}{33}=\frac{2}{33}
Divide the numbers
x^{2}=\frac{2}{33}
Take the root of both sides of the equation and remember to use both positive and negative roots
x=\pm \sqrt{\frac{2}{33}}
Simplify the expression
More Steps
Evaluate
\sqrt{\frac{2}{33}}
To take a root of a fraction,take the root of the numerator and denominator separately
\frac{\sqrt{2}}{\sqrt{33}}
Multiply by the Conjugate
\frac{\sqrt{2}\times \sqrt{33}}{\sqrt{33}\times \sqrt{33}}
Multiply the numbers
\frac{\sqrt{66}}{\sqrt{33}\times \sqrt{33}}
When a square root of an expression is multiplied by itself,the result is that expression
\frac{\sqrt{66}}{33}
x=\pm \frac{\sqrt{66}}{33}
\text{Separate the equation into }2\text{ possible cases}
\begin{align}&x=\frac{\sqrt{66}}{33}\\&x=-\frac{\sqrt{66}}{33}\end{align}
\begin{align}&x=0\\&x=\frac{\sqrt{66}}{33}\\&x=-\frac{\sqrt{66}}{33}\end{align}
Solution
x_{1}=-\frac{\sqrt{66}}{33},x_{2}=0,x_{3}=\frac{\sqrt{66}}{33}
Alternative Form
x_{1}\approx -0.246183,x_{2}=0,x_{3}\approx 0.246183
Show Solutions
