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Question
2\times \frac{d!}{d+1}
Simplify the expression
\frac{2\times d!}{d+1}
Evaluate
2\times \frac{d!}{d+1}
Solution
\frac{2\times d!}{d+1}
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Find the excluded values
d=-1
Evaluate
\left(2\times \frac{d!}{d+1}\right)
To find the excluded values,set the denominators equal to 0
d+1=0
Move the constant to the right-hand side and change its sign
d=0-1
Solution
d=-1
Show Solutions
