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Question
\frac{16}{7}=b^{2}
Solve the quadratic equation
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Solve using square roots
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Solve using the quadratic formula
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Solve using the PQ formula
b_{1}=-\frac{4\sqrt{7}}{7},b_{2}=\frac{4\sqrt{7}}{7}
Alternative Form
b_{1}\approx -1.511858,b_{2}\approx 1.511858
Evaluate
\frac{16}{7}=b^{2}
Swap the sides
b^{2}=\frac{16}{7}
Take the root of both sides of the equation and remember to use both positive and negative roots
b=\pm \sqrt{\frac{16}{7}}
Simplify the expression
b=\pm \frac{4\sqrt{7}}{7}
\text{Separate the equation into }2\text{ possible cases}
\begin{align}&b=\frac{4\sqrt{7}}{7}\\&b=-\frac{4\sqrt{7}}{7}\end{align}
Solution
b_{1}=-\frac{4\sqrt{7}}{7},b_{2}=\frac{4\sqrt{7}}{7}
Alternative Form
b_{1}\approx -1.511858,b_{2}\approx 1.511858
Show Solutions
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